Question

Answer the following to 4 decimals of accuracy. For a group of 10 students taken at...

Answer the following to 4 decimals of accuracy.
For a group of 10 students taken at random from the test described above with standard deviation 6 points,
the average was found to be 74. Find a 95% confidence interval around this mean.

Homework Answers

Answer #1

The 95% confidence interval around this mean is (69.708,78.292)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
⦁   Given the following GPA for 4 students: 2, 3, 3, 4. Age of students are:...
⦁   Given the following GPA for 4 students: 2, 3, 3, 4. Age of students are: 10, 11, 12, 15. There are 10,000 total students. Average GPA: Unknown, Standard Deviation of GPA: 0.02 and it’s Normal. ⦁   Find the mean and standard deviation for GPA. (10 points) ⦁   Calculate a 95% confidence interval for the populations mean GPA. (5 points) ⦁   Use Correlation formula to find r between GPA and Age. (10 points) ⦁   Find Regression Line Equation. (5 points)...
A sample of grade point averages was recently taken from a group of individuals who recently...
A sample of grade point averages was recently taken from a group of individuals who recently passed the California Bar Exam. The results were: 3.06, 3.56, 3.20, 2.87, 3.3, 3.61, 3.75, 3.1, 4, 3.65. Find the sample mean and sample standard deviation for these results. Find the 95% confidence interval for the mean G.P.A. of students who pass the California Bar Exam. Suppose that another sample was taken of 30 people who recently passed the California Bar Exam, and the...
A group of statistics students decided to conduct a survey at their university to find the...
A group of statistics students decided to conduct a survey at their university to find the average (mean) amount of time students spent studying per week. They sampled 240 students and found a mean of 22.3 hours per week. Assuming a population standard deviation of six hours, what is the confidence interval at the 95% level of confidence? (Please use Student's t distribution at infinite degrees of freedom for three decimal accuracy of the required z value.) a. 21.54 and...
3. Given the following GPA for 4 students: 2, 3, 3, 4. Age of students are:...
3. Given the following GPA for 4 students: 2, 3, 3, 4. Age of students are: 10, 11, 12, 15. There are 10,000 total students. Average GPA: Unknown, Standard Deviation of GPA: 0.02 and it’s Normal. a. Find the mean and standard deviation for GPA. b. Calculate a 95% confidence interval for the populations mean GPA.
Students in a chemistry class convince their teacher to use the following "group grading" scenario. Students...
Students in a chemistry class convince their teacher to use the following "group grading" scenario. Students will all take the exam on their own; however, the grade they receive will be the mean of their test score with 4 other randomly selected classmates. Assume that the test scores for this particular exam are normally distributed with a mean of 74 and a standard deviation of 12 points. You need an 80 or better on this exam. What is the probability...
A group of 51 randomly selected students have a mean score of 29.5 with a sample...
A group of 51 randomly selected students have a mean score of 29.5 with a sample standard deviation of 5.2 on a placement test. What is the 95% confidence interval for the mean score, μ, of all students taking the test? Critical error= Margin of error= confidence interval=
From a random sample of 66 students in an introductory finance class that uses​ group-learning techniques,...
From a random sample of 66 students in an introductory finance class that uses​ group-learning techniques, the mean examination score was found to be 79.84 and the sample standard deviation was 2.5 For an independent random sample of 88 students in another introductory finance class that does not use​ group-learning techniques, the sample mean and standard deviation of exam scores were 73.38 and 8.5 respectively. Estimate with 95​% confidence the difference between the two population mean​ scores; do not assume...
A random sample of 121 NKU students was taken to test the proportion of students who...
A random sample of 121 NKU students was taken to test the proportion of students who had attended a Reds game in 2015. 95% confidence interval results: Variable Count Total Sample Prop. Std. Err. L. Limit U. Limit Reds 65 121 0.53719008 0.045328634 0.44834759 0.62603257 1. Verify that the conditions are met to construct a 95% confidence interval for the proportion of NKU students who attended a Reds game in 2015. 2. Construct a 95% confidence interval: 3. Interpret the...
Suppose that the IQ’s of School A's students can be described by a Normal model with...
Suppose that the IQ’s of School A's students can be described by a Normal model with a mean of 130 and a standard deviation of 8 points. Also suppose that the IQ’s of students from School B can be described by a Normal model with mean of 120 and standard deviation of 10 points. We select 1 student at random from School A. Find the probability that this student’s IQ is at least 125 points. Suppose that the IQ’s of...
Your class has been given a test to assess educational experience. The mean on the test...
Your class has been given a test to assess educational experience. The mean on the test was 74 and the standard deviation was 10. Assuming a normal distribution, use this information and the standard normal table to answer questions 12-15. You must show all work to receive credit. Round to 3 decimal places throughout. 12. What percentage of students scored between 77 and 86? (6 points) 13. What percentage of students scored between 67 and 91? (6 points) 14. What...