A governmental agency computed the proportion of violent crimes in the United States in a particular year falling into each of four categories. A simple random sample of
550 violent crimes committed in California during that year were categorized in the same way. The following table presents the results.
Category | U.S. Proportion |
California Frequency |
---|---|---|
Murder |
0.012 |
5 |
Forcible Rape |
0.074 |
33 |
Robbery |
0.360 |
201 |
Aggravated Assault |
0.554 |
311 |
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Can you conclude that the proportions of crimes in the various categories in California differ from those in the United States as a whole? Use the
0.05 level of significance and the P-value method with the TI-84 Plus calculator.
Part 1 of 4
Your Answer is correct
(a) State the null and alternate hypotheses.
H0
: The proportions of crimes in the various categories in California ▼are the same as those in the United States as a whole.
H1
: The proportions of crimes in the various categories in California ▼are not the same as those in the United States as a whole.
Part: 1 / 4
1 of 4 Parts Complete
Part 2 of 4
(b) Find the P-value. Round the answer to at least four decimal places.
The P -value is . |
H0 : The proportions of crimes in the various categories in California are the same as those in the United States as a whole.
H1 : The proportions of crimes in the various categories in California are not the same as those in the United States as a whole.
Part 2 of 4
applying chi square goodness of fit test: |
relative | observed | Expected | residual | Chi square | |
category | frequency(p) | Oi | Ei=total*p | R2i=(Oi-Ei)/√Ei | R2i=(Oi-Ei)2/Ei |
1 | 0.012 | 5 | 6.60 | -0.62 | 0.388 |
2 | 0.074 | 33 | 40.70 | -1.21 | 1.457 |
3 | 0.360 | 201 | 198.00 | 0.21 | 0.045 |
4 | 0.554 | 311 | 304.70 | 0.36 | 0.130 |
total | 1.000 | 550 | 550 | 2.0203 | |
test statistic X2 = | 2.020 |
degree of freedom =categories-1= | 3 |
p value = | 0.5682 (form excel function chidist(2.020,3) |
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