Question

A data set includes

103103

body temperatures of healthy adult humans having a mean of

98.198.1degrees°F

and a standard deviation of

0.560.56degrees°F.

Construct a

9999​%

confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of

98.6degrees°F

as the mean body​ temperature?

Answer 1

t critical value at 0.01 level with 102 df = 2.625

99% confidence interval for is

- t * S / sqrt(n) < < + t * S / sqrt(n)

98.1 - 2.625 * 0.56 / sqrt( 103) < < 98.1 + 2.625 * 0.56 / sqrt( 103)

97.955 < < 98.245

99% CI is ( 97.955 , 98.245 )

Since 98.6 contained in confidence interval, we have sufficient evidence to conclude that mean body

temperature of 98.6 is accepted.