Question

A professor records the time (in minutes) that it takes 16 students to complete an exam. Compute the SS, the variance, and the standard deviation assuming the 16 students constitute a population and assuming the 16 students constitute a sample. (Round your answers for variance and standard deviation to two decimal places.) 38 22 49 32 37 47 36 31 44 19 43 13 20 24 39 46

(a) the 16 students constitute a population

SS

variance standard

(b) the 16 students constitute a sample

SS

Variance

Standard deviation

Answer #1

Ans:

xi | (xi-33.75)^2 | |

1 | 38 | 18.0625 |

2 | 22 | 138.0625 |

3 | 49 | 232.5625 |

4 | 32 | 3.0625 |

5 | 37 | 10.5625 |

6 | 47 | 175.5625 |

7 | 36 | 5.0625 |

8 | 31 | 7.5625 |

9 | 44 | 105.0625 |

10 | 19 | 217.5625 |

11 | 43 | 85.5625 |

12 | 13 | 430.5625 |

13 | 20 | 189.0625 |

14 | 24 | 95.0625 |

15 | 39 | 27.5625 |

16 | 46 | 150.0625 |

Total |
540 |
1891 |

mean |
33.75 |

a)SS=1891

Population Variance=1891/16**=118.19**

Population standard
deviation=sqrt(1891/16)**=10.87**

b)

SS=1891

Sample Variance=1891/(16-1)**=126.07**

Sample standard
deviation=sqrt(1891/(6-1))**=11.23**

A professor records the time (in minutes) that it takes 16
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and assuming the 16 students constitute a sample. (Round your
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variance, and the standard deviation assuming the 16 students
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sample. (Round your answers for variance and standard deviation to
two decimal places.)
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16
49
40
27
39
38
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23
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22
35
46
50
52
42
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A professor records the time (in minutes) that it takes 16
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variance, and the standard deviation assuming the 16 students
constitute a population and assuming the 16 students constitute a
sample. (Round your answers for variance and standard deviation to
two decimal places.)
27
39
19
46
41
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41
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31
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16
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QUESTION 24
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44
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49
51
53
54
55
55
57
57
57
58
59
59
59
59
60
60
60
60
60
62
62
62
64
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75
75
77
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88
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equation editor
Equation Editor
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equation editor
Equation...

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