A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 110.9-cm and a standard
deviation of 0.6-cm. For shipment, 7 steel rods are bundled
Find the probability that the average length of a randomly selected bundle of steel rods is less than 110.9-cm.
P(M < 110.9-cm) = ______________
Enter your answer as a number accurate to 4 decimal places.
Given that ,
mean = = 110.9-cm
standard deviation = = 0.6-cm
n = 7
M = 110.9-cm
M = / n = 0.6 / 7 = 0.2268
P(M < 110.9-cm) = P((M - M) / M < (110.9 - 110.9) / 0.2268)
= P(z < 0)
P(M < 110.9-cm) = 0.5000
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