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A 3.10 oz movie theater box of peanut M&M’s has a mean weight of 3.12 oz...

A 3.10 oz movie theater box of peanut M&M’s has a mean weight of 3.12 oz with a standard deviation of 0.09 oz. Assume the weight of the boxes is Normal Distributed.

a. What is the probability that the box of M&M’s is underweight?

b. If 15 boxes were sampled, what percentage of those boxes would be between 3.09 and 3.11 ounces?

Math   Statistics-And-Probability   
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Answer #1

Answer a) The probability that the box of M&M’s is underweight is 0.4129

Answer b) The percentage of those boxes would be between 3.09 and 3.11 ounces is 23.51 percent

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