Question

1. A drug manufacturer advertises that the mean time that a particular product dissolves in gastric juice is no more than 45 seconds. Health Canada believes that the drug manufacturer is false advertising and collects data. Assume the population distribution of dissolve times is normal.

Specify the null and alternative hypotheses by matching to the correct choice.

H₀ :   

1. μ= 45 seconds

2. ?¯= 45 seconds

3. ?¯ ≠ 45 seconds

4. μ ≠ 45 seconds

H_A :   

1. μ= 45 seconds

2. ?¯= 45 seconds

3. ?¯ ≠ 45 seconds

4. μ ≠ 45 seconds

2. A drug manufacturer advertises that the mean time that a particular product dissolves in gastric juice is no more than 45 seconds. Health Canada believes that the drug manufacturer is false advertising and collects data. Assume the population distribution of dissolve times is normal.

Using standard notation, define the population parameter of interest.

Select One:

a. ?¯= the sample mean drug dissolve time in gastric juice

b. μ= the mean drug dissolve time in gastric juice

c. μ= the sample mean drug dissolve time in gastric juice

d. ?¯= the mean drug dissolve time in gastric juice

e. ?¯= the true mean drug dissolve time in gastric

f. μ= the true mean drug dissolve time in gastric juice

Answer 1

Given,

A drug manufacturer advertises that the mean time that a particular product dissolves in gastric juice is no more than 45 seconds and Health Canada believes that the drug manufacturer is false advertising. Also given that the population distribution of dissolve times is norma;

Answer 1:
Here, the null hypothesis H0: = 45 seconds (Option1)

and alternate hypothesis HA: ≠ 45 seconds (Option 4)

Answer 2:
Here, the appropriate option is Option f

that is, that is the population parameter of interest is = the true mean drug dissolve time in gastric juice