Question

if the mean stature of a worker population is 60inches with a variance of 6.25 inches, what is the stature of an individual at the 95th percentile? please show all work, thank you.

Answer 1

Solution:-

Given that,

mean = = 60

variance = 2  =  6.25

standard deviation = = 2  =  6.25 = 2.5

Using standard normal table,

P(Z < z) = 95%

= P(Z < z ) = 0.95

= P(Z < 1.645 ) = 0.95

z = 1.645

Using z-score formula,

x = z * +

x = 1.645 * 2.5 + 60

x = 64.1 inches