Question

Dean Halverson recently read that full-time college students study 20 hours each week. She decides to do a study at her university to see if there is evidence to show that this is not true at her university. A random sample of 33 students was asked to keep a diary of their activities over a period of several weeks. It was found that the average number of hours that the 33 students studied each week was 22.2 hours. The sample standard deviation of 3.9 hours. Find the p-value.

The p-value should be rounded to 4-decimal places.

Answer 1

Given that, sample size (n) = 33, sample mean = 22.2 hours

and sample standard deviation (s) = 3.9 hours

The null and alternative hypotheses are,

H0 : μ = 20 hours

Ha : μ ≠ 20 hours (claim)

This test is two-tailed test.

Test statistic is,

=> Test statistic = t = 3.241

Degrees of freedom = 33 - 1 = 32

Using Excel we get, the p-value as follows :

Excel Command : =TDIST (3.241, 32, 2) = 0.0028

=> p-value = 0.0028