Question

NASA is conducting an experiment to find out the fraction of people who black out at...

NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 66.

Step 2 of 2:

Suppose a sample of 566 people is drawn. Of these people, 260 passed out. Using the data, construct the 95% confidence interval for the population proportion of people who black out at G forces greater than 6. Round your answers to three decimal places.

Answer

Lower endpoint:       Upper endpoint:

Homework Answers

Answer #1

Solution :

Given that,

Point estimate = sample proportion = = x / n = 260 / 566 = 0.459

1 - = 1 - 0.459 = 0.541

  Z/2 = Z0.025 = 1.96

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.96 (((0.459 * 0.541) / 566)

= 0.041

A 95% confidence interval for population proportion p is ,

± E

0.459  ± 0.041

Lower endpoint: 0.418

Upper endpoint: 0.500

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