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given normal random variable Z with mean μ= 57.1 and standard deviation σ=13.2, what is P...

given normal random variable Z with mean μ= 57.1 and standard deviation σ=13.2, what is P (Z > 46)?

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Answer #1

solution :

Given ,

mean = = 57.1

standard deviation = =13.2

P(x > 46) =

= 1 - P[ X - ) / / < (46-57.1) /13.2 ]

= 1 - P(z <-0.84 )

Using z table

= 1 - 0.2005

probability= 0.7995

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