Question

A political candidate has asked you to conduct a poll to
determine what percentage of people support her.

If the candidate only wants a 9% margin of error at a 95%
confidence level, what size of sample is needed?

Give your answer in whole people.

Answer #1

Solution :

Given that,

= 0.5

1 - = 0.5

margin of error = E = 9% = 0.09

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025= 1.96 ( Using z table )

Sample size = n = (Z/2 / E)2 * * (1 - )

= (1.96 / 0.09)2 * 0.5 * 0.5

= 118.5679

Sample size =119

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