Question

(1 point) Starting salaries of 135 college graduates who have taken a statistics course have a mean of $42,583. The population standard deviation is known to be $9,171. Using 99% confidence, find both of the following:

A. The margin of error:

B. Confidence interval: ,

Answer #1

Sample Size (n) = | 135 |

Population Standard Deviation (SD) = | 9171 |

Mean = | 42583 |

Ans A

Z score for 99% confidence = | 2.58 |

Margin of Error = (2.58 * 9171)/(135)^(1/2) = | 2036.43 |

Ans B

Confidence Interval = Mean +/- (margin of Error) | |

Lower End of the Interval = Mean - (margin of Error) = | 40546.57 |

Upper End of the Interval = Mean + (margin of Error) = | 44619.43 |

Starting salaries of 64 college graduates who have taken a
statistics course have a mean of $42,500 with a standard deviation
of $6,800. Find a 68% confidence interval for ?μ. (NOTE: Do not use
commas or dollar signs in your answers. Round each bound to three
decimal places.)

Starting salaries of 64 college graduates who have taken a
statistics course have a mean of $43,500 with a standard deviation
of $6,800. Find a 68% confidence interval for μ. (NOTE: Do not use
commas or dollar signs in your answers. Round each bound to three
decimal places.)
Lower-bound:
Upper-bound:

Salaries of 45 college graduates who took a statistics course in
college have a mean, overbar x, of comma $65,500. Assuming a
standard deviation, sigmaσ, of $14 comma 14,971, construct a
99% confidence interval for estimating the population mean μ.
$ less than< μless than<$

Salaries of 47 47 college graduates who took a statistics course
in college have a mean, x overbar x, of $ 63 comma 400 $63,400.
Assuming a standard deviation, sigma σ, of $ 11 comma 850
11,850, construct a 99 99% confidence interval for estimating the
population mean mu μ.

How to calculate margin of error for this question?
Starting salaries of 80 college graduates who have taken a
statistics course have a mean of $42,893. Suppose the distribution
of this population is approximately normal and has a standard
deviation of $10,748.
Use a 93% confidence level.
Can't get the answer right :(

Salaries of 45 college graduates who took a statistics course in
college have a mean, x overbar , of $ 65 comma 900 . Assuming a
standard deviation, sigma , of $12 comma 992 , construct a 95 %
confidence interval for estimating the population mean u .

Salaries of 4747 college graduates who took a statistics course
in college have a mean, x overbarx, of $63,000. Assuming a
standard deviation, sigmaσ, of $16 comma 37216,372, construct
a
9090% confidence interval for estimating the population mean
μ.
(Round to the nearest integer as needed.)

Salaries of 44 college graduates who took a statistics course in
college have a mean,xbar,of $63,600.Assuming a standard
deviation,σ,of $12,063,construct a 95% confidence interval for
estimating the population mean μ.
____< mu<____

Salaries of 34 college graduates who took a statistics course in
college have a mean, x overbar, of $ 68 comma 500. Assuming a
standard deviation, sigma, of $12 comma 046, construct a 99%
confidence interval for estimating the population mean mu. Click
here to view a t distribution table.LOADING... Click here to view
page 1 of the standard normal distribution table.LOADING... Click
here to view page 2 of the standard normal distribution
table.LOADING... $ nothingless than muless than$ nothing...

Question 3 4 pts
A sample of salaries of 57 college graduates who took a
statistics course in college have a mean of $78,829 and a
standard deviation of $10,086. Construct a 91% confidence
interval for estimating the population mean.

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