As of March 2018, the unemployment rate is 4.1, which means that there is a 4.1% probability that a working age adult is unemployed.
1. If we surveyed 100 adults, what is the probability that exactly 5 of them are unemployed?
2. What is the probability that no more than 2 are unemployed?
Mean = np = 100 * 0.041 = 4.1
Standard deviation = sqrt( np(1-p))
= sqrt( 100 * 0.041 * 0.959)
= 1.9829
a)
Using normal approximation
P( X < x) = P( Z < x - mean / SD)
With continuity correction,
P(X = 5) = P(4.5 < X < 5.5 )
= P( X < 5.5) - P( X < 4.5)
= P(Z < 5.5 - 4.1 / 1.9829) - P(Z < 4.5 - 4.1 / 1.9829)
= P( Z < 0.7060) - P( Z < 0.2017)
= 0.7599 - 0.5799
= 0.1800
b)
P( X <= 2) = P( Z <2.5 - 4.1 /1.9829)
= P(Z < -0.8069)
= 0.2099
Get Answers For Free
Most questions answered within 1 hours.