Question

In a test of the effectiveness of garlic for lowering​ cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes​ (before minus​ after) in their levels of LDL cholesterol​ (in mg/dL) have a mean of 0.3 and a standard deviation of 24.6 Use a 0.10 significance level to test the claim that with garlic​ treatment, the mean change in LDL cholesterol is greater than 0.

What do the results suggest about the effectiveness of the garlic​ treatment? Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.

What are the null and alternative​ hypotheses?

A.

H_0: μ = 0 mg/dl

H_1: μ ≠ 0 mg/dl

B.

H_0: μ = 0 mg/dl

H_1: μ < 0 mg/dl

C.

H_0: μ = 0 mg/dl

H_1: μ > 0 mg/dl

D.

H_0: μ > 0 mg/dl

H_1: μ < 0 mg/dl

Determine the test statistic:

​(Round to two decimal places as​ needed.)

Determine the​ P-value. :

​(Round to three decimal places as​ needed.)

State the final conclusion that addresses the original claim.

Fail to reject

Upper H 0H0.

There is

not sufficient

evidence to conclude that the mean of the population of changes

is greater than

00.?

Answer 1

Solution :

The null and alternative hypothesis is ,

H0 : = 0 mg/dl

Ha : > 0 mg/dl

Test statistic (t) =

= ( - ) / s / n

= (0.3 - 0) / 24.6 / 64

Test statistic = 0.10

P-value = 0.4613

= 0.10

P-value >

Fail to reject the H0.

There is no sufficient evidence to support the claim.