Question

In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.3 and a standard deviation of 24.6 Use a 0.10 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0.

What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.

What are the null and alternative hypotheses?

A.

H_{0:} μ = 0 mg/dl

H_{1}_{:} μ ≠ 0 mg/dl

B.

H_{0:} μ = 0 mg/dl

H_{1}_{:} μ < 0 mg/dl

C.

H_{0:} μ = 0 mg/dl

H_{1}_{:} μ > 0 mg/dl

D.

H_{0:} μ > 0 mg/dl

H_{1}_{:} μ < 0 mg/dl

Determine the test statistic:

(Round to two decimal places as needed.)

Determine the P-value. :

(Round to three decimal places as needed.)

State the final conclusion that addresses the original claim.

Fail to reject

Upper H 0H0.

There is

not sufficient

evidence to conclude that the mean of the population of changes

is greater than

00.?

Answer #1

Solution :

The null and alternative hypothesis is ,

H0 : = 0 mg/dl

Ha : > 0 mg/dl

Test statistic (t) =

= ( - ) / s / n

= (0.3 - 0) / 24.6 / 64

Test statistic = 0.10

P-value = 0.4613

= 0.10

P-value >

Fail to reject the H0.

There is no sufficient evidence to support the claim.

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