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A random of 900 people in New York, 326 of them are lefty. A. Find the...

A random of 900 people in New York, 326 of them are lefty. A. Find the margin error E with 95% confident level. B. Find 95% confident interval estimate of the proportion of lefty.

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Answer #1

A random of 900 people in New York, 326 of them are lefty.

sample proportion pf lefty = 326/900 = 0.3622

A) A 95% confidence level has significance level of 0.05 and critical value is

Margin of error ( E ) is,

The margin of error ( E ) = 0.0314

B) The 95% confidence interval for p is,

Therefore, the  95% confident interval estimate of the proportion of lefty is ( 0.3308, 0.3936 )

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