Question

A political candidate has asked you to conduct a poll to
determine what percentage of people support her.

If the candidate only wants a 8% margin of error at a 99%
confidence level, what size of sample is needed?

Give your answer in whole people.

Answer #1

Solution :

Given that,

= 0.5

1 - = 1 - 0.5 = 0.5

margin of error = E = 8% = 0.08

At 99% confidence level the z is,

= 1 - 99%

= 1 - 0.99 = 0.01

/2 = 0.005

Z/2 = 2.576 ( Using z table )

Sample size = n = (Z/2 / E)2 * * (1 - )

= (2.576 / 0.08)2 * 0.5 * 0.5

=259.21

Sample size = 259

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