Question

a random sample of 20 recent weddings in a country yielded a mean wedding cost of...

a random sample of 20 recent weddings in a country yielded a mean wedding cost of $26,325.57. assume the wedding cost in this country are normally distributed with a standard deviation of $7700.
determine a 95% confidence interval for the mean cost of all recent weddiings in this country.
the 95% confidence interval is from $__ to $__.

Homework Answers

Answer #1

TOPIC:Confidence interval for the population mean.

the 95% confidence interval is from $22,950.90 to $29,700.24.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample of 20 recent weddings in a country yielded a mean wedding cost of...
A random sample of 20 recent weddings in a country yielded a mean wedding cost of $26,395.79. Assume that recent wedding costs in this country are normally distributed with a standard deviation of ​$8500 a. Determine a​ 95% confidence interval for the mean​ cost,μ​,of all recent weddings in this country. B. margin of error
According to a popular wedding magazine, the mean cost of flowers for a wedding is $750....
According to a popular wedding magazine, the mean cost of flowers for a wedding is $750. Recently, in a random sample of 45 weddings in the US it was found that the average cost of the flowers was $734, with a standard deviation of $102. On the basis of this, a 90% confidence interval for the mean cost of flowers for a wedding is $701 to $767. Choose the statement that is the best interpretation of the confidence interval. Select...
A random sample of 20 observations is used to estimate the population mean. The sample mean...
A random sample of 20 observations is used to estimate the population mean. The sample mean and the sample standard deviation are calculated as 152 and 74, respectively. Assume that the population is normally distributed. What is the margin of error for a 95% confidence interval for the population mean? Construct the 95% confidence interval for the population mean. Construct the 90% confidence interval for the population mean. Construct the 78% confidence interval for the population mean. Hint: Use Excel...
In a random sample of six mobile​ devices, the mean repair cost was $75.00 and the...
In a random sample of six mobile​ devices, the mean repair cost was $75.00 and the standard deviation was $13.0013.00. Assume the population is normally distributed and use a​ t-distribution to find the margin of error and construct a 95​% confidence interval for the population mean. Interpret the results. The 95​% confidence interval for the population mean μ is
Canadian couples spend an average of $25038 to cover the cost of their weddings. Determine the...
Canadian couples spend an average of $25038 to cover the cost of their weddings. Determine the cutoff of the top 10% of wedding costs if the standard deviation is $2094 and the data is normally distributed (USING EXCEL SOFTWARE)
A random sample of 24 observations is used to estimate the population mean. The sample mean...
A random sample of 24 observations is used to estimate the population mean. The sample mean and the sample standard deviation are calculated as 104.6 and 28.8, respectively. Assume that the population is normally distributed. Construct the 90% confidence interval for the population mean. Then, construct the 95% confidence interval for the population mean. Finally, use your answers to discuss the impact of the confidence level on the width of the interval.
1) The mean height of women in a country (ages 20-29) is 64.3 inches. A random...
1) The mean height of women in a country (ages 20-29) is 64.3 inches. A random sample of 75 women in this age group is selected. What is the probability that the mean height for the sample is greater than 65 inches? assume σ = 2.59 The probability that the mean height for the sample is greater than 65 inches is __. 2) Construct the confidence interval for the population mean μ C=0.95 Xbar = 4.2 σ=0.9 n=44 95% confidence...
In a random sample of 13 microwave​ ovens, the mean repair cost was ​$70.00 and the...
In a random sample of 13 microwave​ ovens, the mean repair cost was ​$70.00 and the standard deviation was ​$15.40. Using the standard normal distribution with the appropriate calculations for a standard deviation that is​ known, assume the population is normally​ distributed, find the margin of error and construct a 98​% confidence interval for the population mean. A 98​% confidence interval using the​ t-distribution was (58.5,81.5). Find the margin of error of the population mean. Find the confidence interval of...
In a random sample of six mobile devices, the mean repair cost was $60.00 and the...
In a random sample of six mobile devices, the mean repair cost was $60.00 and the standard deviation was $12.50. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 99% confidence interval for the population mean. Interpret the results. The 99% confidence interval for the population μ is (_, _)
A random sample of 91 fields of barley has a mean yield of 41.2 bushels per...
A random sample of 91 fields of barley has a mean yield of 41.2 bushels per acre and standard deviation of 4.64 bushels per acre. Determine the 95% confidence interval for the true mean yield. Assume the population is normally distributed. Step 2 of 2 : Construct the 95% confidence interval. Round your answer to one decimal place.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT