Question

a random sample of 20 recent weddings in a country yielded a mean wedding cost of...

a random sample of 20 recent weddings in a country yielded a mean wedding cost of $26,325.57. assume the wedding cost in this country are normally distributed with a standard deviation of $7700.
determine a 95% confidence interval for the mean cost of all recent weddiings in this country.
the 95% confidence interval is from $__ to $__.
Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

TOPIC:Confidence interval for the population mean.

the 95% confidence interval is from $22,950.90 to $29,700.24.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample of 24 observations is used to estimate the population mean. The sample mean...
A random sample of 24 observations is used to estimate the population mean. The sample mean and the sample standard deviation are calculated as 104.6 and 28.8, respectively. Assume that the population is normally distributed. Construct the 90% confidence interval for the population mean. Then, construct the 95% confidence interval for the population mean. Finally, use your answers to discuss the impact of the confidence level on the width of the interval.
1) The mean height of women in a country (ages 20-29) is 64.3 inches. A random...
1) The mean height of women in a country (ages 20-29) is 64.3 inches. A random sample of 75 women in this age group is selected. What is the probability that the mean height for the sample is greater than 65 inches? assume σ = 2.59 The probability that the mean height for the sample is greater than 65 inches is __. 2) Construct the confidence interval for the population mean μ C=0.95 Xbar = 4.2 σ=0.9 n=44 95% confidence...
Canadian couples spend an average of $25038 to cover the cost of their weddings. Determine the...
Canadian couples spend an average of $25038 to cover the cost of their weddings. Determine the cutoff of the top 10% of wedding costs if the standard deviation is $2094 and the data is normally distributed (USING EXCEL SOFTWARE)
In a random sample of 13 microwave​ ovens, the mean repair cost was ​$70.00 and the...
In a random sample of 13 microwave​ ovens, the mean repair cost was ​$70.00 and the standard deviation was ​$15.40. Using the standard normal distribution with the appropriate calculations for a standard deviation that is​ known, assume the population is normally​ distributed, find the margin of error and construct a 98​% confidence interval for the population mean. A 98​% confidence interval using the​ t-distribution was (58.5,81.5). Find the margin of error of the population mean. Find the confidence interval of...
In a random sample of six mobile devices, the mean repair cost was $60.00 and the...
In a random sample of six mobile devices, the mean repair cost was $60.00 and the standard deviation was $12.50. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 99% confidence interval for the population mean. Interpret the results. The 99% confidence interval for the population μ is (_, _)
A random sample of 91 fields of barley has a mean yield of 41.2 bushels per...
A random sample of 91 fields of barley has a mean yield of 41.2 bushels per acre and standard deviation of 4.64 bushels per acre. Determine the 95% confidence interval for the true mean yield. Assume the population is normally distributed. Step 2 of 2 : Construct the 95% confidence interval. Round your answer to one decimal place.
In a random sample of 39 residents of the state of Florida, the mean waste recycled...
In a random sample of 39 residents of the state of Florida, the mean waste recycled per person per day was 2.1 pounds with a standard deviation of 0.87 pounds. Determine the 95% confidence interval for the mean waste recycled per person per day for the population of Florida. Assume the population is normally distributed. Step 2 of 2 : Construct the 95% confidence interval. Round your answer to one decimal place.
URGENTTTTTT A random sample of 20 maximum sentences for murder yielded the​ data, in​ months, presented...
URGENTTTTTT A random sample of 20 maximum sentences for murder yielded the​ data, in​ months, presented to the right. Use the technology of your choice to complete parts​ (a) through​ (d) below. 254 345 304 299 275 265 338 284 293 269 262 308 371 298 277 269 258 294 279 293 a. Find a 99​% confidence interval for the mean maximum sentence of all murders. Assume a population standard deviation of 35 months. The confidence interval is from nothing...
In a random sample of 20 people with advance degree in biology, the mean monthly income...
In a random sample of 20 people with advance degree in biology, the mean monthly income was $4744 and the standard deviation was $580. Assume income are normally distributed. a. Construct 99% confidence interval for the mean monthly income for people with advance degrees in biology. b. What happens to the width of the confidence interval if you construct a 90% confidence level. (Does width get wider or narrower?) c. How does the width of the confidence interval change if...
1. A random sample of 100 households in Skagit County yielded an average household income of...
1. A random sample of 100 households in Skagit County yielded an average household income of $71,000, with a sample standard deviation of $3,800. Assume the distribution of household income is Normal. a. Use this information to compute a 95% confidence interval for the population mean household income in Skagit County. Please clearly show that you checked to make sure the data meet all necessary conditions for inference. b. Interpret the meaning of the confidence interval you found in part...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT