Question

For the following event probabilities: P(A)=0.9330, P(B)=0.9890, P(C)=0.4830, P(AnB)=0.9330, P(AnC)=0.4640, P(BnC)=0.4720, P(AnBnC)=0.4640, P(AuB)=0.9890, P(AuC)=0.9520, P(BuC)=1.0000, P(A|B)=0.9434,...

For the following event probabilities:

P(A)=0.9330, P(B)=0.9890, P(C)=0.4830, P(AnB)=0.9330, P(AnC)=0.4640, P(BnC)=0.4720, P(AnBnC)=0.4640, P(AuB)=0.9890, P(AuC)=0.9520, P(BuC)=1.0000, P(A|B)=0.9434, P(A|C)=0.9607, P(B|C)=0.9772, find P(AuBuC).

Math   Statistics-And-Probability   
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Answer #1

P(A B C) = P(A) + P(B) + P(C) - P(A B) - P(A C) - P(B C) + P(A B C)

P(A) = 0.9330

P(B) = 0.9890

P(C) = 0.4830

P(A B) = 0.9330

P(A C) = 0.4640

P(B C) = 0.4720

P(A B C) = 0.4640

P(A B C) = 0.9330 + 0.9890 + 0.4830 - 0.9330 - 0.4640 - 0.4720 + 0.4640

= 1

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