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A) A survey says average spent for eating out is $120 pear week. Standard deviation is...

A) A survey says average spent for eating out is $120 pear week. Standard deviation is $42 What is the z-score to be in the top 10.03%?

B) what is the actual score needed to be in the top 10.03%?

(calculate to 2 decimal digits)

Math   Statistics-And-Probability   
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