Question

Research showed mean income of $48,000. Standard deviation was $10,000. what is the probability that a...

Research showed mean income of $48,000. Standard deviation was $10,000.

what is the probability that a person would earn between $46,000 and $56,100?

Homework Answers

Answer #1

Let X be the amount that the person earn.

Then,  

We need to find the probability that that the person earn between $46000 and $56100.

That is, we need to find P(46000<X<56100).

From standard normal table, P(-0.2<z<0.81)= 0.3703

Required probability= 0.3701

Please upvote my answer if you find it helpful. Thanking you.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A) Research showed mean income of $48,000. Standard deviation was $10,000. What is the probability that...
A) Research showed mean income of $48,000. Standard deviation was $10,000. What is the probability that someone earns less than $54,000? B) Using information from the above question, what is the probability that a person would have more than $65,200?
According to a marketing research firm, the mean ATM withdrawals is $65. Assume the standard deviation...
According to a marketing research firm, the mean ATM withdrawals is $65. Assume the standard deviation for withdrawals is 35. The distribution of all ATM withdrawals is skewed right. If a random sample of 50 ATM withdrawals is chosen, what is the probability the sample mean will be between $72 and $75?
1. IQ tests are normally distributed with a mean of 100 and a standard deviation of...
1. IQ tests are normally distributed with a mean of 100 and a standard deviation of 15. Find the following probabilities: A) If a person is randomly selected, what is the probability that the person had an IQ greater than125? _________________ b) If a person is randomly selected what is the probability that the person has an IQ below 92? c) If 40 people are randomly selected, what is the probability that their mean IQ is between 98 and 108?
the mean is 15.2 and standard deviation is 0.9 find the probability that x is greater...
the mean is 15.2 and standard deviation is 0.9 find the probability that x is greater than 14.1? the mean is 15.2 and standard deviation is 0.9 find the probability that x is between nd 16.6 ?
suppose that probability distribution that mean 20 and standard deviation 3. According to chebychev inequality what...
suppose that probability distribution that mean 20 and standard deviation 3. According to chebychev inequality what is the probability that an outcome lies between 16 and 24?
the mean per capita income is 21053 dollars per annum with a standard deviation of 805...
the mean per capita income is 21053 dollars per annum with a standard deviation of 805 dollars per annum, what is the probability that the samele mean would differ from the true mean by greater than 167 is a sample of 71 persons is selected
the mean per capita income is 21,604 dollars per annum with a standard deviation of 727...
the mean per capita income is 21,604 dollars per annum with a standard deviation of 727 dollars per annum. what is the probability that the sample mean would differ from the true mean by less than 36 dollars if a sample of 193 persons is randomly selected?
The breaking strength of a rivet has a mean value of 10,000 psi and a standard...
The breaking strength of a rivet has a mean value of 10,000 psi and a standard deviation of 498 psi. (a) What is the probability that the sample mean breaking strength for a random sample of 40 rivets is between 9,900 and 10,200? (Round your answer to four decimal places.)
The mean income of a group of sample observations is $500, and the standard deviation is...
The mean income of a group of sample observations is $500, and the standard deviation is $30. According to Chebyshev’s Theorem, at least what percent of the incomes will lie between $410 and $590?
The mean per capita income is 17,145dollars per annum with a standard deviation of 505 dollars...
The mean per capita income is 17,145dollars per annum with a standard deviation of 505 dollars per annum. What is the probability that the sample mean would differ from the true mean by greater than 40 dollars if a sample of 466 persons is randomly selected? Round your answer to four decimal places.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT