The mean consumption of water per household in a city was 1238 cubic feet per month. Due to a water shortage because of a drought, the city council campaigned for water use conservation by households. A few months after the campaign was started, the mean consumption of water for a sample of 96 households was found to be 1153 cubic feet per month. The population standard deviation is given to be 261 cubic feet.
a. Find the p-value for the hypothesis test that the mean consumption of water per household has decreased due to the campaign by the city council. Would you reject the null hypothesis at α=0.01?
b. Make the test of part a
using the critical-value approach and α=0.01.
Round your answer for z to two decimal places.
Solution :
= 1238
=1153
=261
n = 96
This is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 1238
Ha : 1238
Test statistic = z
= ( - ) / / n
= (1153 - 1238) / 261 / 96
= -3.19
Test statistic = z = -3.19
P(z < -3.19 ) = 0.0007
P-value = 2*0.0007 =0.0014
= 0.05
P-value <
0.0014 < 0.01
Reject the null hypothesis .
There is sufficient evidence to suggest that
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