For questions 24 – 25 answer all the following questions:
a)State the Null and Alternate Hypotheses
b) Which is the claim?
c) Will you use a z-test, t-test or chi-square test? What is the critical value?
d) Describe the reject region as left tailed, right tailed or two-tailed.
e) Find the sample statistic.
f) Do you reject the claim? Write out your decision in at least one sentence.
24. The Healthy Food Company makes an Oatmeal and Almond cereal. It has three competitors who make a similar product. The company wants to investigate if the percentage of people who consume Oatmeal and Almond cereal is the same for each of the four brands. Let A represent the Healthy Food Company’s and B, C and D represent the 3 competitors. A sample of 1000 person who consume Oatmeal and Almond cereal and they were asked which brand they consumed. The results are provided in the table below.
Cereal Brand |
A |
B |
C |
D |
Consumption |
212 |
284 |
254 |
250 |
Does the sample provided on this table provide enough evidence to reject the null hypothesis that the percentage of people who consume Oatmeal and Almond cereal is the same for all four brands? Use a significance level of 5%
Ans:
a)
H0: Percentage of people who consume Oatmeal and Almond cereal is the same for all four brands
Ha:Percentage of people who consume Oatmeal and Almond cereal is not the same for all four brands.
b)H0 is claim
c)Chi square test
df=4-1=3
alpha=0.05
critical chi square value=CHIINV(0.05,3)=7.815
d)Right tailed
Reject H0,if chi square>7.815
e)
Expected count=1000/4=250
Brand | Observed(fo) | Expected | (fo-fe)^2/fe |
A | 212 | 250 | 5.776 |
B | 284 | 250 | 4.624 |
C | 254 | 250 | 0.064 |
D | 250 | 250 | 0 |
Total | 1000 | 1000 | 10.464 |
Test statistic:
Chi square=10.464
f)As,test statistic is greater than 7.815,we Reject H0.
There is sufficient evidence to reject the null hypothesis that the percentage of people who consume Oatmeal and Almond cereal is the same for all four brands.
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