The owner of Showtime Movie Theaters, Inc., would like to predict weekly gross revenue as a function of advertising expenditures. Historical data for a sample of eight weeks follow.
Weekly Gross Revenue ($1,000s) |
Television Advertising ($1,000s) |
Newspaper Advertising ($1,000s) |
---|---|---|
96 | 5.0 | 1.5 |
90 | 2.0 | 2.0 |
95 | 4.0 | 1.5 |
92 | 2.5 | 2.5 |
95 | 3.0 | 3.3 |
94 | 3.5 | 2.3 |
94 | 2.5 | 4.2 |
94 | 3.0 | 2.5 |
(a)
Develop an estimated regression equation with the amount of television advertising as the independent variable. (Round your numerical values to two decimal places. Let x1 represent the amount of television advertising in $1,000s and y represent the weekly gross revenue in $1,000s.)
ŷ = ______________
Predict weekly gross revenue (in dollars) for a week when $3,200 is spent on television advertising and $1,700 is spent on newspaper advertising. (Round your answer to the nearest cent.)
$ _____________
(b)
Develop an estimated regression equation with both television advertising and newspaper advertising as the independent variables. (Round your numerical values to two decimal places. Let x1 represent the amount of television advertising in $1,000s, x2 represent the amount of newspaper advertising in $1,000s, and y represent the weekly gross revenue in $1,000s.)
ŷ = ___________
a)
using excel data analysis tool for regression,steps are: write data>menu>data>data analysis>regression>enter required labels>ok> and following o/p is obtained
Regression Statistics | ||||||
Multiple R | 0.8078 | |||||
R Square | 0.6526 | |||||
Adjusted R Square | 0.5946 | |||||
Standard Error | 1.2152 | |||||
Observations | 8 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 1 | 16.6 | 16.6 | 11.27 | 0.0153 | |
Residual | 6 | 8.9 | 1.5 | |||
Total | 7 | 25.5 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 88.6377 | 1.5824 | 56.0159 | 0.0000 | 84.7658 | 92.5096 |
X | 1.6039 | 0.4778 | 3.3569 | 0.0153 | 0.4348 | 2.7730 |
so, regression line is Ŷ =
88.64 + 1.60 *Tv Ads
=======================
SUMMARY OUTPUT | ||||||||
Regression Statistics | ||||||||
Multiple R | 0.958663 | |||||||
R Square | 0.919036 | |||||||
Adjusted R Square | 0.88665 | |||||||
Standard Error | 0.642587 | |||||||
Observations | 8 | |||||||
ANOVA | ||||||||
df | SS | MS | F | Significance F | ||||
Regression | 2 | 23.43541 | 11.7177 | 28.377768 | 0.001865 | |||
Residual | 5 | 2.064592 | 0.412918 | |||||
Total | 7 | 25.5 | ||||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | |
Intercept | 83.23009 | 1.573869 | 52.88248 | 4.572E-08 | 79.18433 | 87.27585 | 79.18433 | 87.27585063 |
X Variable 1 | 2.290184 | 0.304065 | 7.531899 | 0.0006532 | 1.508561 | 3.071806 | 1.508561 | 3.071806446 |
X Variable 2 | 1.300989 | 0.320702 | 4.056697 | 0.0097608 | 0.476599 | 2.125379 | 0.476599 | 2.125378798 |
win % = 83.23 + 2.29*TV Ads + 1.30*newspaper Ads
win % = 83.23 + 2.29*3.2 + 1.30*1.7 = 92.77%
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