You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 40 bacteria reveals a sample mean of ¯x=78 hours with a standard deviation of s=4 hours. You would like to estimate the mean lifespan for this species of bacteria to within a margin of error of 0.7 hours at a 90% level of confidence.
What sample size should you gather to achieve a 0.7 hour margin of error? Round your answer up to the nearest whole number.
n = ? bacteria
Solution :
Given that,
standard deviation =s = =4
Margin of error = E = 0.7
At 90% confidence level of z is
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645
sample size = n = [Z/2* / E] 2
n = ( 1.645 *4 /0.7 )2
n =88.36
Sample size = n =88 rounded
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