For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. In a random sample of 70 professional actors, it was found that 37 were extroverts.
(a) Let p represent the proportion of all actors who are extroverts. Find a point estimate for p. (Round your answer to four decimal places.)
(b) Find a 95% confidence interval for p. (Round your answers to two decimal places.)
lower limit-
upper limit-
Solution :
Given that,
a) Point estimate = sample proportion = = x / n = 37 / 70 = 0.5286
1 - = 1 - 0.5286 = 0.4714
b) Z/2 = Z0.025 = 1.96
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.96 (((0.5286 * 0.4714) / 70)
= 0.12
A 95% confidence interval for population proportion p is ,
± E
= 0.5286 ± 0.12
= ( 0.41, 0.65 )
lower limit = 0.41
upper limit = 0.65
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