Subject # | Honesty | Satisfaction |
1 | 5 | 9 |
2 | 3 | 2 |
3 | 7 | 10 |
4 | 2 | 6 |
5 | 4 | 4 |
6 | 6 | 7 |
1)Given the data illustrated in the table above, compute the equation for the linear regression line (i.e. y = mx+b) (7--pts)
2)Based on the regression line you computed, what is the likely level of satisfaction if a person were to have an honesty level
a.2.5
b.8?
c.3.5?
We can use here Excel for regression equation
Step 1) Enter data in Excel .
Step 2) Data >>Data analysis >>Regression
>>Select y and x values separately >>Ok
1) Regression equation is ,
y=1.1429x+1.1905
2) Substitute given values of x in regression equation and solve it.
a) For x=2.5 then y= 1.1429(2.5)+1.1905
=4.05
b) For x=8 , then y= 1.1429(8)+1.1905
=10.33
c) For x=3.5 then y= 1.1429(3.5)+1.1905
=5.19
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