Question

If I am conducting an experiment with taste and there are 20 cups total, 9 of...

If I am conducting an experiment with taste

and there are 20 cups total, 9 of the answers were correct and the p-hat = 9/20 = .45 or 45%

and the H0: P = .5
and the HA: P < .5

Significance level or alpha = 0.05

what is the p-value for the observed p-hat and how does it compare to the alpha?


please answer, asap.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
An experiment compares the taste of instant coffee with fresh-brewed coffee. Each subject tastes two unmarked...
An experiment compares the taste of instant coffee with fresh-brewed coffee. Each subject tastes two unmarked cups of coffee, one of each type, in random order and states which he or she prefers. Of the 60 subjects who participate in the study, 25 prefer instant coffee and the other 35 prefer fresh-brewed. Take p to be the proportion of the population that prefers fresh-brewed coffee. Test the claim that a majority of coffee drinkers prefer the taste of fresh-brewed coffee,...
Question 4 please although I am unsure of my answers for the rest as well :(...
Question 4 please although I am unsure of my answers for the rest as well :( Here is the full list for background info. Consider a significance test for a null hypothesis versus a two-sided alternative. State all values of a standard normal test statistic z that will give a result significant at the 10% level but not at the 5% level of significance. (Sec. 6.2) You perform 1,000 significance tests using α = 0.01. Assuming that all the null...
9. Grades and AM/PM Section of Stats: There were two large sections of statistics this term...
9. Grades and AM/PM Section of Stats: There were two large sections of statistics this term at State College, an 8:00 (AM) section and a 1:30 (PM) section. The final grades for both sections are summarized in the contingency table below. Observed Frequencies: Oi's A B C D F Totals AM 6 11 17 20 18 72 PM 19 19 17 13 8 76 Totals 25 30 34 33 26 148 The Test: Test for a significant dependent relationship between...
The local public transport authority is conducting research into commuter behaviour. A previous census indicated that...
The local public transport authority is conducting research into commuter behaviour. A previous census indicated that the mean commuter time was 45 minutes with a standard deviation of 9.0 minutes. After some recent infrastructure upgrades and a new train timetable, the transport authority would like to test whether average commuter time has decreased. A random sample of 50 commuter times has been collected. 35.5 38 45.2 37.3 43.9 44.7 56.7 51.7 46.2 30.7 32.5 54.6 54.7 37 20.6 56.1 39.4...
9. There are two sections of statistics, one in the morning (AM) with 20 students and...
9. There are two sections of statistics, one in the morning (AM) with 20 students and one in the afternoon (PM) with 31students. Each section takes the identical test. The PM section, on average, scored higher than the AM section. The results are summarized in the table below. Necessary information: n x s2 s   PM (x1) 31 81.4 277.5 16.66   AM (x2) 20 71.5 250.3 15.82   The Test: Test the claim that the PM section did significantly better than the...
ran an experiment to test optimum power and time settings for microwave popcorn. HerHer goal was...
ran an experiment to test optimum power and time settings for microwave popcorn. HerHer goal was to deliver popcorn with fewer than 10​% of the kernels left​ unpopped, on average. SheShe determined that power 9 at 4 minutes was the best combination. To be sure that the method was​ successful, sheshe popped 8 more bags of popcorn​ (selected at​ random) at this setting. All were of high​quality, with the percentages of unpopped kernels shown below. 6.3 13.21 9.9 3.3 2.1...
9. For the next three questions, use the following information to determine your answers: A survey...
9. For the next three questions, use the following information to determine your answers: A survey was sent out to re-evalute the proportion of people who play games on pc computers, as the last study on the topic had been gathered four years prior. The current study, with 861 participants, found that 53% of people who responded play on a pc computer. Calculate the 90% confidence interval. Enter your answer in the following format: (lower_value, upper_value). Please round your values...
An experiment was conducted to compare broadleaf seedling growth by treating the seedling soil weeds with...
An experiment was conducted to compare broadleaf seedling growth by treating the seedling soil weeds with one of two fertilizers. Thirty of 75 seedlings were randomly chosen to receive Fertilizer X. The rest received Fertilizer Y. The heights were recorded for each seedling, in centimeters, at the end of the study. The results obtained are shown. Fertilizer X: X̄1 = 72.4 cm, s1 = 9 cm Fertilizer Y: X̄2 = 86.1 cm, s2 = 8 cm We wish to determine...
***please use rstudio and describe how to answer this*** I am not learning to do this...
***please use rstudio and describe how to answer this*** I am not learning to do this by hand - a handwritten answer does not help me in the slightest. I need to know how do a hypothesis test in r but my professor did a very poor job of explaining it. An Office of Admission document at a certain university claims that 54.3% of their undergraduates are female. To test this claim, a random sample of 220 undergraduates was selected....
Consider the following data on x = rainfall volume (m3) and y = runoff volume (m3)...
Consider the following data on x = rainfall volume (m3) and y = runoff volume (m3) for a particular location. x 5 12 14 16 23 30 40 47 55 67 72 83 96 112 127 y 4 10 13 14 15 25 27 45 38 46 53 67 82 99 105 Use the accompanying Minitab output to decide whether there is a useful linear relationship between rainfall and runoff. The regression equation is runoff = -1.82 + 0.839 rainfall...