Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value t Subscript alpha divided by 2tα/2, (b) find the critical value z Subscript alpha divided by 2zα/2, or (c) state that neither the normal distribution nor the t distribution applies. Here are summary statistics for randomly selected weights of newborn girls: nequals=239239, x overbarxequals=33.433.4 hg, sequals=7.97.9 hg. The confidence level is 9595%.
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. t Subscript alpha divided by 2tα/2equals= nothing (Round to two decimal places as needed.)
B. z Subscript alpha divided by 2zα/2equals= nothing (Round to two decimal places as needed.)
C. Neither the normal distribution nor the t distribution applies.
The confidence interval for true mean based on the sample mean is
The summary statistics for randomly selected weights of newborn girls: , , .
The confidence level is 95%.
Since the population standard deviation is not known, we use Student's t-distribution.
For
A) The critical values are .
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