Question

If the sampled population has a mean 48 and standard deviation
18, then the mean and the standard deviation for the sampling
distribution of (X-bar) for n = 9 are:

A. 48 and 18

B. 48 and 9

C. 16 and 6

D. 48 and 6

E. 48 and 2

Answer #1

Solution :

Given that,

mean = = 48

standard deviation = =18

n = 9

The sampling distribution of mean and standard deviation is ,

= 48 and

= / n = 9 / 18 = 2

The mean and the standard deviation for the sampling
distribution of (X-bar) for n = 9 are:**48 and 2**

**option E.**

If the sampled population has a mean 48 and standard deviation
18, then the mean and the standard deviation for the sampling
distribution of (X-bar) for n = 9 are:
A. 48 and 18
B. 48 and 9
C. 16 and 6
D. 48 and 6
E. 48 and 2

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