Question

HW 19

A student conducts a survey of students regarding how many units they plan to take in the fall semester. She collects data, and finds that 26 out of 80 plan to take 15 units or more. Find the 99% confidence interval for the proportion of students who plan to take 15 or more units in the fall semester.

*What is the sample proportion?                            [ Select ]                       ["0.1875", "26", "0.5769", "0.325"]      

*What is zα/2zα/2?                             [ Select ]                       ["1.96", "1.645", "2.576", "2.326"]      

*What is the margin of error                            [ Select ]                       ["0.048", "0.0225", "0.052", "0.135", "0.103"]      

*What are the lower and upper bounds for the confidence interval?                            [ Select ]                       ["Lower bound = 27.2%, upper bound = 37.5%", "Lower bound = 21%, upper bound = 44%", "Lower bound = 22.2%, upper bound = 42.8%", "Lower bound = 19%, upper bound = 46%"]      

*What is the correct interpretation of the confidence interval?                            [ Select ]                       ["We are 99% confident that the true proportion of students taking 15 or more units is in our interval.", "We are 95% confident that the true proportion of students taking 15 or more units is in our interval.", "99% of intervals are taking 15 units or more.", "99% of the time, students will take more than 15 units."]      

Answer 1