Question

A company produces steel rods. The lengths of the steel rods are normally distributed with a...

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 179-cm and a standard deviation of 2.4-cm. For shipment, 12 steel rods are bundled together.

Find the probability that the average length of a randomly selected bundle of steel rods is less than 177.8-cm.
P(M < 177.8-cm) =

Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

Homework Answers

Answer #1

= 179 cm

= 2.4 cm

n = 12

According to Central Limit Theorem, the distribution of sample mean will be approximately normal.

P( < A) = P(Z < (A - )/)

= = 179 cm

=

=

= 0.69282

P(M < 177.8 cm) = P(Z < (177.8 - 179)/0.69282)

= P(Z < -1.732)

= 0.0416

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 246.7-cm and a standard deviation of 0.8-cm. For shipment, 23 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 246.6-cm. P(M > 246.6-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are...
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 197.5-cm and a standard deviation of 2-cm. For shipment, 6 steel rods are bundled together. Find P11, which is the average length separating the smallest 11% bundles from the largest 89% bundles. P11 =______________ -cm Enter your answer as a number accurate to 2 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 179.5-cm and a standard deviation of 0.7-cm. For shipment, 20 steel rods are bundled together. Find P95, which is the average length separating the smallest 95% bundles from the largest 5% bundles. P95 = -cm Enter your answer as a number accurate to 2 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 263.6 cm and a standard deviation of 0.5 cm. For shipment, 27 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is less than 263.6 cm. P(¯xx¯ < 263.6 cm) = Enter your answer as a number accurate to 4 decimal places. Answers should be obtained using zz scores rounded to...
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 110.9-cm and a standard deviation of 0.6-cm. For shipment, 7 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is less than 110.9-cm. P(M < 110.9-cm) = ______________ Enter your answer as a number accurate to 4 decimal places.
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 153.6 cm and a standard deviation of 2.1 cm. For shipment, 13 steel rods are bundled together. Note: Even though our sample size is less than 30, we can use the z score because 1) The population is normally distributed and 2) We know the population standard deviation, sigma. Find the probability that the average length of a randomly selected bundle of...
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 91.1-cm and a standard deviation of 0.5-cm. For shipment, 25 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 90.8-cm. P(M > 90.8-cm) =
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 226.6-cm and a standard deviation of 1.7-cm. For shipment, 10 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is less than 227.9-cm. P(M < 227.9-cm) =
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 211.4-cm and a standard deviation of 1.3-cm. For shipment, 5 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 211.5-cm. P(M > 211.5-cm) =
A company produces steel rods. The lengths of the steel rods are normally distributed with a...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 133.8-cm and a standard deviation of 0.6-cm. For shipment, 8 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 133.8-cm and 134.2-cm. P(133.8-cm < M < 134.2-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT