Question

lets say we take an SRS of people at campus and record all of their ages. id like to use this to prove or disprove the claim that the mean age of student at campus is over 22. now from our simple random sample at campus of 207 people, we have a mean age of 21.84 with a sample standard deviation of 1.2. Run a hypothesis test to find evidence for or against our claim.

A) What's our hypothesis?

B) Whats your conclusion? The evidence suggests that with a test statistic of -1.91, we reject the null OR the evidence suggests that with a p value of .97, the mean age of students across campus isnt above 22.

Answer 1

Solution :

= 22

= 21.84

s = 1.2

n = 207

This is the right tailed test .

The null and alternative hypothesis is

H0 :   = 22

Ha : > 22  

Test statistic = t

= ( - ) / s / n

= (21.84 - 22) /1.2 / 207

= -1.918

p(t >-1.918 ) = 1-P (t< -1.918) =0.9718

P-value = 0.9718

No significance level available i think

Do not reject the null ,not enough evidence to suggest that