For a particular brand of SUV, you want to estimate the miles per gallon (mpg). The manufacturer says that σ = 1.75 mpg. Find the sample size if you want a margin of error of ± 0.55 and 90% confidence?
Solution :
Given that,
standard deviation = = 1.75
margin of error = E = 0.55
At 90%confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z0.05 = 1.645
Sample size = n = ((Z/2 * ) / E)2
= ((1.645 * 1.75) /0.55 )2
= 27
Sample size = 27
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