Suppose a population of FORMER high school graduates in Wisconsin is normally distributed with a mean age of 24 years and a standard deviation is 1.25 years. Consider a sample size of 100 high school graduates. Find the probability that the sample mean age of these students greater than 24.3 years.
Solution :
Given that ,
mean = = 24
standard deviation = = 1.25
n = 100
= 24
= / n =1.25 / 100 = 0.125
P( >24.3 ) = 1 - P( < 24.3)
= 1 - P[( - ) / < (24.3-24) /0.125 ]
= 1 - P(z <2.4 )
Using z table
= 1 - 0.9918
probability= 0.0082
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