The ticket sales for events held at the new civic center are believed to be normally distributed with a mean of 12,000 and a standard deviation of 1,000.
a. |
What is the probability of selling more than 10,000 tickets? |
b. |
What is the probability of selling between 9,500 and 11,000 tickets? |
c. |
What is the probability of selling more than 13,500 tickets? |
Solution :
a.
P(x > 10000) = 1 - P(x < 10000)
= 1 - P[(x - ) / < (10000 - 12000) / 1000)
= 1 - P(z < -2)
= 1 - 0.0228
= 0.9772
probability = 0.9772
b.
P(9500 < x < 11000) = P[(9500 - 12000)/ 1000) < (x - ) / < (11000 - 12000) / 1000) ]
= P(-2.5 < z < -1)
= P(z < -1) - P(z < -2.5)
= 0.1587 - 0.0062
= 0.1525
probability = 0.1525
c.
P(x > 13500) = 1 - P(x < 13500)
= 1 - P[(x - ) / < (13500 - 12000) / 1000)
= 1 - P(z < 1.5)
= 1 - 0.9332
= 0.0668
probability = 0.0668
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