Question

Assume that adults have IQ scores that are normally distributed with a mean of 101.2 and a standard deviation 23.6 Find the first quartile Upper Q 1Q1, which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.) The first quartile is

Answer #1

Solution:-

Given that,

mean = = 101.2

standard deviation = = 23.6

Using standard normal table,

The z dist'n First quartile is,

P(Z < z) = 25%

= P(Z < z) = 0.25

= P(Z < -0.67 ) = 0.25

z = -0.67

Using z-score formula,

x = z * +

x = -0.67 * 23.6+101.2

x = 85.388

First quartile =Q1 = 86

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