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The age (X) and glucose levels (Y) of 6 patients are
calculated in order to see if there is a relationship
between these two variables. The following data was
collected:
SP xy = 478
SS x = 1241
SS y = 656
Calculate the correlation coefficient using the formula: r = SPxy /
√ SSx SSy => [sq root of SSx SSy ]
----------------------------
Using the correlation coefficient (r) derived from above
and the data indicated below, determine
(1) the regression equation and (2) the standard error of the
estimate using the following formulas:
_ _
Least Squares Regression Equation: Y’ = bX + a where a = Y - bX and
b = SSy/SSx • r => sq rt of SSy/SSx
Standard Error of the Estimate: Sy|x = SSy (1 – r 2
)/n-2 [take sq root of entire fraction]
_
also, X = 4.2
_
Y = 81
------------------------------
Given the regression equation determined in problem
immediately above, answer the following:
A. What is the predicted glucose level of a patient whose age is
43?
B. What is the predicted glucose level of a patient whose age is
59?
Calculate the correlation coefficient
r = SPxy / √ SSx SSy
r= 478 / sqrt(1241*656)
r= 0.5298
(1) the regression equation and (2) the standard error of the estimate using the following formulas:
b = SSy/SSx
b = 656/1241
b = 0.5286
a = Y – bX
a = 81 -0.5286*4.2
a=78.7799
y=78.7799 + 0.5286*x
Given the regression equation determined in problem immediately above, answer the following:
A. What is the predicted glucose level of a patient whose age is 43?
y=78.7799 + 0.5286*x
y=78.7799 + 0.5286*43
y= 101.5097
B. What is the predicted glucose level of a patient whose age is 59?
y=78.7799 + 0.5286*x
y=78.7799 + 0.5286*59
y= 109.9673
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