Question

Please write the answer legibly. Thank you. The age (X) and glucose levels (Y) of 6...

Please write the answer legibly. Thank you.

The age (X) and glucose levels (Y) of 6 patients are calculated in order to see if there is a relationship
between these two variables. The following data was collected:
SP xy = 478
SS x = 1241
SS y = 656
Calculate the correlation coefficient using the formula: r = SPxy / √ SSx SSy => [sq root of SSx SSy ]

----------------------------

Using the correlation coefficient (r) derived from above and the data indicated below, determine
(1) the regression equation and (2) the standard error of the estimate using the following formulas:
_ _
Least Squares Regression Equation: Y’ = bX + a where a = Y - bX and b = SSy/SSx • r => sq rt of SSy/SSx

Standard Error of the Estimate: Sy|x = SSy (1 – r 2 )/n-2 [take sq root of entire fraction]
_
also, X = 4.2
_
Y = 81

------------------------------

Given the regression equation determined in problem immediately above, answer the following:
A. What is the predicted glucose level of a patient whose age is 43?
B. What is the predicted glucose level of a patient whose age is 59?

Homework Answers

Answer #1

Calculate the correlation coefficient

r = SPxy / √ SSx SSy

r= 478 / sqrt(1241*656)

r= 0.5298

(1) the regression equation and (2) the standard error of the estimate using the following formulas:

b = SSy/SSx

b = 656/1241

b = 0.5286

a = Y – bX

a = 81 -0.5286*4.2

a=78.7799

y=78.7799 + 0.5286*x

Given the regression equation determined in problem immediately above, answer the following:

A. What is the predicted glucose level of a patient whose age is 43?

y=78.7799 + 0.5286*x

y=78.7799 + 0.5286*43

y= 101.5097

B. What is the predicted glucose level of a patient whose age is 59?

y=78.7799 + 0.5286*x

y=78.7799 + 0.5286*59

y= 109.9673

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