A researcher wishes to estimate the mean weight of Americans within 1 pound. What sample size should be chosen to find the mean weight at a 98% confidence level? Suppose we know that the population standard deviation is 3 pounds.
a. |
752 |
|
b. |
5 |
|
c. |
48 |
|
d. |
49 |
Solution :
Given that,
Population standard deviation = = 3
Margin of error = E = 1
At 98% confidence level the z is,
= 1 - 98%
= 1 - 0.98 = 0.02
/2 = 0.01
Z/2 = Z 0.01 = 2.326
sample size = n = [Z/2* / E] 2
n = [ 2.326 * 3 / 1 ]2
n = 48.69
Sample size = n = 49
Correct option ; - ( d )
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