Question

In a recent poll, 150 people were asked if they liked dogs, and 57% said they did. Find the Margin of Error for this poll, at the 99% confidence level. Give your answer to three decimal places if possible.

Answer #1

Solution :

Given that,

- =57%=0.57

1 - = 1 - 0.57 = 0.43

n=150

At 99% confidence level the z is ,

= 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

Z_{/2}
= Z_{0.005} = 2.57

Margin of error = E = Z_{
/ 2} * ((
* (1 -
)) / n)

= 2.576 * (((0.57 * 0.43) / 150) = 0.104

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[,]

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