Question

Given a standard normal​ distribution, find the value of k such that

​(a)​P(Z>​k)=0.2877​;

​(b) P(Z<​k)=0.0375;

​(c) P(−0.82<Z<​k)=0.6749

Answer 1

Answer :-

a)​

P(Z>​k)=0.2877​

By using inverse normal table

k = 0.56

b)

P(Z<​k)=0.0375

By using inverse normal table

k = -1.78

c)

P(−0.82<Z<​k)=0.6749

P(Z < k) - P(Z < -0.82) = 0.6749

P(Z < k ) - 0.2061= 0.6749

P( Z < k ) = 0.4688

By using inverse normal table

k = -0.078

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