use the given data to find the minimum sample size required to estimate a population proportion or percentage margin of error 3 percentage points confidence level 90% from a prior study p is estimated by the decimal equivalent of 38% N equals?
Solution :
Given that,
= 0.38
1 - = 0.62
margin of error = E = 0.03
At 90% confidence level the z is ,
Z/2 = Z0.05 = 1.645
sample size = n = (Z / 2 / E )2 * * (1 - )
= (1.645/0.03)2 * 0.38*0.62
= 708.38
sample size = 708
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