Determine the total area under the standard normal curve for parts (a) through (c) below. For each, be sure to draw a standard normal curve and shade the area that is to be found.
Click here to view the standard normal distribution table (page 1).
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Click here to view the standard normal distribution table (page 2).
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(a) Determine the total area under the standard normal curve to the left of
zequals=negative 2−2
or to the right of
zequals=22.
Draw a standard normal curve and shade the area that is to be found. Choose the correct graph below.
Click here to view graph a.
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Click here to view graph c.
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Click here to view graph b.
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Click here to view graph d.
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The total area under the standard normal curve to the left of
zequals=negative 2−2
or to the right of
zequals=22
is
. 0456.0456.
(Round to four decimal places as needed.)
(b) Determine the total area under the standard normal curve to the left of
zequals=negative 2.41−2.41
or to the right of
zequals=1.411.41.
Draw a standard normal curve and shade the area that is to be found. Choose the correct graph below.
Click here to view graph c.
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Click here to view graph d.
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Click here to view graph a.
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Click here to view graph b.
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The total area under the standard normal curve to the left of
zequals=negative 2.41−2.41
or to the right of
zequals=1.411.41
is
nothing.
(Round to four decimal places as needed.)
(c) Determine the total area under the standard normal curve to the left of
zequals=negative 0.19−0.19
or to the right of
zequals=1.341.34.
Draw a standard normal curve and shade the area that is to be found. Choose the correct graph below.
Click here to view graph c.
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Click here to view graph d.
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Click here to view graph b.
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Click here to view graph a.
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The total area under the standard normal curve to the left of
zequals=negative 0.19−0.19
or to the right of
zequals=1.341.34
is
nothing.
(Round to four decimal places as needed.)
Click to select your answer(s).
(a)
P(left of -2 or right of 2) = 1-0.9544 = 0.0456 (ans)
(b)
P(left of -2.41 or right of 1.41) = 1-0.9127 = 0.0873 (ans)
(c)
P(left of -0.19 or right of 1.34) = 1-0.4852 = 0.5148 (ans)
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