Question

The manufacturer of a particular cold medicine claims that its’ product provides relief from symptoms in...

The manufacturer of a particular cold medicine claims that its’ product provides relief from symptoms in 30.00 minutes, on average.

To test this claim ( i.e., the “null hypothesis” is that the population mean = 30.00), a sample of 144 cold sufferers were offered the medicine ( so, “n” = 144).

The ( sample) mean time to relief was 31.14 minutes, with a standard deviation = 9.00 minutes.

a.) Can the manufacturer’s claim be rejected, based on this sample (use an “alpha” = .05, employing a two-tailed test)? Show your work.

b.) Solve for the p-value of the test.

c.) In general, would a large p-value or a small p-value tend to support the manufacturer’s claim? Explain.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The manufacturer of an over-the-counter pain reliever claims that its product brings pain relief to headache...
The manufacturer of an over-the-counter pain reliever claims that its product brings pain relief to headache suffers in less than 3.5 minutes, on average. In order to be able to make this claim in its television advertisements, the manufacturer was required by a particular television network to present statistical evidence in support of the claim. The manufacturer reported that for a sample of 50 headache sufferers, the mean time to relief was 3.11 minutes and the standard deviation was 69.84...
The manufacturer of an over-the-counter heartburn relief medication claims that its product brings relief in less...
The manufacturer of an over-the-counter heartburn relief medication claims that its product brings relief in less than 3.0 minutes, on average. To be able to make this claim, the manufacturer was required by the FDA to present statistical evidence in support of the claim. The manufacturer reported that for a sample of 100 heartburn sufferers, the mean time to relief was 3.3 minutes and the population standard deviation was 1.1 minutes. What is the probability of obtaining a sample with...
A manufacturer claims that their product has the mean value m = 42.1. A customer wanted...
A manufacturer claims that their product has the mean value m = 42.1. A customer wanted to check this claim. He collected a sample (n = 25) from the manufacturer and obtained the sample mean of 47.5 and standard deviation s = 8.4. Does the customer’s test support the manufacturer’s claim? (use a = 0.05). Please draw the distribution curve and indicate rejection regions.
The label on the cold medicine Dozenol lists 600 mg of acetaminophen per fluid ounce as...
The label on the cold medicine Dozenol lists 600 mg of acetaminophen per fluid ounce as an active ingredient. The FDA tests 64 one-ounce portions of the medicine and finds that the mean amount of acetaminophen for this sample is 589 mg with a standard deviation of 21 mg. Test the claim of the FDA that the medicine does not contain the required amount of acetaminophen. Use a 0.05 level of significance. a. Identify the null and alternate hypothesis. b....
The manufacturer of an airport baggage scanning machine claims it can handle an average of 530...
The manufacturer of an airport baggage scanning machine claims it can handle an average of 530 bags per hour. (a-1) At α = .05 in a left-tailed test, would a sample of 16 randomly chosen hours with a mean of 510 and a standard deviation of 50 indicate that the manufacturer’s claim is overstated? Choose the appropriate hypothesis.(Multiple Choice) a. H1: μ < 530. Reject H1 if tcalc > –1.753 b. H0: μ < 530. Reject H0 if tcalc >...
A seat belt manufacturer, who provides seat belts for Volkswagen cars, claims that his product has...
A seat belt manufacturer, who provides seat belts for Volkswagen cars, claims that his product has a mean breaking strength of 250 kg with a standard deviation of 3.5 kg. You select a random sample of 49 of his seat belts and compute the mean breaking strength of your sample to be 245 kg. Test the manufacturer's claim at (letter alpha) α=.05.
A study conducted by the research department of a pharmaceutical company claims that the annual spending...
A study conducted by the research department of a pharmaceutical company claims that the annual spending (per person) for prescription drugs for allergy relief, μ1 , is greater than or equal to the annual spending (per person) for non-prescription allergy relief medicine, μ2 . A health insurance company conducted an independent study and collected data from a random sample of 235 individuals for prescription allergy relief medicine. The sample mean is found to be 17.7 dollars/year, with a sample standard...
40. A cell phone manufacturer claims that its phone will last for more than 8 hours...
40. A cell phone manufacturer claims that its phone will last for more than 8 hours of continuous talk time when the battery is fully charged. To test this claim at a​ 10% level of​ significance, a random sample of 18 phones were selected. The results showed a sample mean of 8.2 hours and a sample standard deviation of 0.4 hour. Based on the data and hypothesis​ test, can you dispute the cell phone​ manufacturer’s claim? A. YES B. NO...
A hair dryer manufacturer claims that the mean life of its product is greater than 700...
A hair dryer manufacturer claims that the mean life of its product is greater than 700 hours. A random sample of 40 of its motors have a mean life of 702 hours. It is known that the standard deviation of the lifetime of the motors is 15 hours. At  = 0.06, is there enough evidence to reject the company's claim? Perform a thorough hypothesis test on your work including: Identification of the null and alternative hypotheses and indication of which is...
A manufacturer claims that the mean life time of its lithium batteries is 1500 hours ....
A manufacturer claims that the mean life time of its lithium batteries is 1500 hours . A home owner selects 30 of these batteries and finds the mean lifetime to be 1470 hours with a standard deviation of 80 hours. Test the manufacturer's claim. Use=0.05. Round the test statistic to the nearest thousandth. a) Hypothesis: b)Critical value (t critical): c)Test statistic (tstat) and the decision about the test statistic:(reject or fail to reject Ho): d)Conclusion that results from the decision...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT