with a mean of 12.5 minutes and a standard deviation of 3.5, considering 121 people are selected, what is the probability that the mean is less than 14 minutes
Given that ,
mean = = 12.5
standard deviation = = 3.5
n = 121
= 12.5
= / n = 3.5/ 121=0.32
P( < 14) = P[( - ) / < (14-12.5) /0.32 ]
= P(z <4.69 )
Using z table
=1
probability= 1
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