T or F
If the test statistic for a left-tailed test is z = – 1.85, then P-value is 0.9678.
Given that the test statistic for a left tailed test is z=-1.85.
Now, the test is left tailed; which means, we have to find the P-value by calculating the area to the left of the test statistic.
So, basically we have to find the area to the left of z=-1.85 for a standard normal distribution.
Now, we have to find
Where, phi is the distribution function of the standard normal variate.
Now, from the standard normal table, this becomes
So, the P-value is 0.0322.
So, the statement " If the test statistic for a left-tailed test is z = – 1.85, then P-value is 0.9678." is a FALSE statement.
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