The accompanying data represent the pulse rates (beats per minute) of nine students enrolled in a statistics course. Treat the nine students as a population. Complete parts (a) through (e).
Student Pulse
Perpectual_Bempah 69
Megan_Brooks 87
Jeff_Honeycutt 79
Clarice_Jefferson 61
Crystal_Kurtenbach 66
Janette_Lantka 81
Kevin_McCarthy 84
Tammy_Ohm 81
Kathy_Wojdya 87
a) Compute the population mean.
b) Compute the population variance.
c) Compute the population standard deviation.
d) What value is the 70th percentile for the data set?
e) Find the percentile rank for the value of 79 in the data set.
f) Find the five-number summary for the data set.
g) Draw a box and whiskers plot using the five-number summary you found in part f.
h) Determine the sample standard deviation of the following simple random samples of size 3.
i Sample 1: {Clarice, Janette, Kevin}
ii Sample 2: {Tammy, Jeff, Megan}
Which samples underestimate the population standard deviation? Which overestimate the population standard deviation?
Solve using Excel functions:
a) Population mean = AVERAGE( ) = 77.22
b) Population variance = VAR.P( ) = 80.62
c) Population standard deviation = STDEV.P( ) = 8.98
d) Arrange ascending order: 61,66,69,79,81,81,84,87,87
70th percentile = (70/100*n)th = (0.7*9)th = 6.3th value = 6th value = 81
e) Percentile rank for the value of 79 = PERCENTRANK.INC(array,79) = 0.38 = 38th percentile
f) Five-number summary:
1. Minimum = MIN( ) = 61
2. Q1 = QUARTILE.EXC(array,1) = 67.5
3. Q2 = MEDIAN( ) = 81
4. Q3 = QUARTILE.EXC(array,3) = 85.5
5. Maximum = MAX( ) = 87
g) Box plot
h) Sample 1 Standard deviation = STEDV.S(61, 81, 84) = 12.5
Sample 2 Standard deviation = STEDV.S(81,79,87) = 4.16
Sample 1 and sample 2 underestimate the population standard deviation.
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