A simple random sample of 100 adults is obtained, and each person’s red blood cell count (in cells per microliter) is measured. The sample mean is 5.20 and the sample standard deviation is 0.50. Use a 0.01 significance level to test the claim that the sample is from a population with a mean less than 5.3, the calculated value of t-test statistic is (Given that H0: µ = 5.3, Ha:µ < 5.3)
1) -20.0
2) -2.0
3) 2.0
4) 20.0
Solution :
Given that,
= 5.3
= 5.20
s = 0.50
n = 100
The null and alternative hypothesis is ,
H0 : = 5.3
Ha : < 5.3
This is the left tailed test .
Test statistic = t
= ( - ) / s / n
= (5.20 - 5.3) / 0.50 / 100
= -2.0
The value of Test statistic is -2.0
Correct option :- 1) -2.0
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