Assume that adults have IQ scores that are normally distributed with a mean of 103.9 and a standard deviation 24.9. Find the first quartile Upper Q 1, which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.) The first quartile
SOLUTION:
Given that,
mean = = 103.9
standard deviation = = 24.9
Using standard normal table,
P(Z < z) = 25%
=(Z < z) = 0.25
= P(Z < z ) = 0.25
z = -0.67
Using z-score formula
x = z +
x = -0.67 *24.9+103.9
x = 87.217
= 103.9
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