Question

Consider the value of t such that the area under the curve between −|t| −|t| and |t| |t| equals 0.98 0.98 . Step 2 of 2: Assuming the degrees of freedom equals 15 15 , determine the t value. Round your answer to three decimal places.

Answer 1

Given that,

degrees of freedom = 15

Using standard normal table,

P( -t < T < t) = 0.98

= P(T < t) - P(Z <-t ) = 0.98

= 2P(T < t) - 1 = 0.98

= 2P(T < t) = 1 + 0.98

= P(T < t) = 1.98 / 2

= P(T < t) = 0.99

= P(T < 2.624) = 0.99

= t ± 2.60248

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